Do Now

Dynamics warm-up: do now
Think about it

When is the acceleration negative? positive?

View the original GIF
Marvin getting smarter

What would happen if this bottle were dropped?

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Newton's Masterpiece!

Newton's Principia, first edition

Sir Isaac Newton's own first edition copy of his Philosophiae Naturalis Principia Mathematica with his handwritten corrections for the second edition.

The first edition was published under the imprint of Samuel Pepys who was president of the Royal Society. By the time of the second edition, Newton himself had become president of the Royal Society, as noted in his corrections.

The book can be seen in the Wren Library of Trinity College, Cambridge.

Photograph © Andrew Dunn, 5 November 2004. www.andrewdunnphoto.com/

4. Standard Equation

Fnet = ma

(N)  =  (Kg)(m/s2)

Newton — force needed to give a 1 kg of mass an acceleration of 1 m/s2

Derived unit — A unit that comes from the combination of other units

N = Kg·m/s2

Fundamental unit (opposite) — m, s, Kg

Force Questions

Ex 1

What is the net force necessary to give a 3.0 kg mass, initially at rest, an acceleration of 5.0 m/s2?

Football player practice toss
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F = ma

(3.0 kg)(5.0 m/s2)

= 15 N

or 15 kg·m/s2

Ex 2

A net force of 30. nt accelerates an object by 15. m/s2. Find the object's mass.

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F = ma

30. N = m(15. m/s2)

m = 2.0 kg

Ex 3

An unbalanced force of 100. nt acts on a 50. kg mass for 5.0 seconds. Find the acceleration of the mass.

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Fnet = ma

100. N = (50. kg)a

a = 2.0 m/s2

Ex 4

A 10. kg cart moving with a velocity of 2.0 m/s is brought to a stop in 2.0 sec. Find the magnitude of the average force used to stop the cart.

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Given

m = 10. kg     t = 2.0 sec

Vi = 2.0 m/s     Vf = 0 m/s (stop)

a = (Vf − Vi) / t

a = (0 − 2.0 m/s) / (2.0 sec)

a = −1.0 m/s2

Fnet = ma

Fnet = (10. kg)(−1.0 m/s2)

Fnet = −10. N

or −10. kg·m/s2

Ex 5

The object below has a mass of 5 kg. Find its acceleration.

20 N and 60 N forces on an object
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Fnet = ma

40 N East = (5 kg)a

a = 8 m/s2 East

Ex 6 Force diagram for the block

The block above has an acceleration of 22. m/s2. What is the mass of the block?

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5 N2 + 10 N2 = R2

Fnet = ma

Fnet = 11 N = m(22 m/s2)

m = .50 kg

Woman kicking a bag

Ex 7 Force diagram for the block

If the magnitude of the block's acceleration is 2.0 m/s2, what is the mass of the block?

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Fnet = ma

10 N Left = m(2 m/s2)

m = 5 kg

Balloon in the Car

Geek question

What will the balloon do when the cart is pushed to the left?

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(Click on image)

Balloon in car - click to play video

Rutgers U

Balloon_in_car

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The air in the container tends to remain at rest. When the cart is pushed to the left, air pressure builds up on the right side of the container.

Try this at home!

Ranking Task

Rank the accelerations

From least to greatest.

Rank the accelerations from least to greatest
Rank the accelerations

From least to greatest.

Force, mass, acceleration diagram 1 Force, mass, acceleration diagram 2

Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. What is one newton?

2. What net force is needed to give a 3.0 kg mass, initially at rest, an acceleration of 5.0 m/s²?

3. A 10. kg cart moving at 2.0 m/s is brought to a stop in 2.0 s. What is the magnitude of the average stopping force?

4. The newton is a derived unit. It is equivalent to…

5. A 5 kg object has a 60 N force pushing it east and a 20 N force pushing it west. What is its acceleration?

NYSSLS Regents Practice · Dynamics · Applying F = ma

Pushing a Grocery Cart

A shopper pushes a 20.-kg grocery cart across a level floor with a horizontal force of 60. N. Friction on the cart’s wheels and axles totals 20. N.

What is the acceleration of the cart?

▶ Want a challenge? Open 6 more Regents-style questions  (harder · mixed formats)

Challenge score: 0 / 6

Substitute values

C1. The shopper pushes harder, with 90. N, while friction stays 20. N. Substitute numerical values into a mathematical representation that can be used to determine the cart’s acceleration. Then calculate the acceleration.

a = Fpush − Ffm = N − N kg = m/s2
Multiple choice

C2. How much horizontal force must the shopper apply to keep the cart moving at constant velocity?

Draw the vector · Determine the magnitude

C3. The cart is rolling to the right when the shopper lets go. Friction (20. N) is now the only horizontal force on the 20.-kg cart. Choose the direction of the cart’s acceleration, and determine its magnitude.

cart
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a = m/s2
Support or Refute · Justify

C4. A student makes the following claim.

Claim: If the shopper pulled the cart from the front with a 60.-N horizontal force instead of pushing it from behind, the cart’s acceleration would be the same.

Place a check mark in either the Support or Refute box. Justify your response using a mathematical relationship.

Multiple choice

C5. Four carts are pushed with these net forces. Which has the greatest acceleration?

Constructed response

C6. A store is considering replacing its 20.-kg steel carts with 12-kg plastic carts with the same wheels. Identify one benefit and one drawback of this change.