Assuming a frictionless, massless pulley, ...

... determine the a of the block after the large block is released

Let's make clockwise positive
Fnet = ma
[Mg - mg] = (M + m)a


g(M - m) = a
(m + M)

Only applies when surface frictionless

Finish This Sentence

According to Newton's 2nd LAw the acceleration of the 2 masses
comes from weight difference and .....

Force of tension of the rope
on mass m, M?
Rule - One Rope, 
One Tension
Let's Make Clockwise Positive
ΣFy = Ma
Mg - Tf = Ma
Tf  = Mg - Ma




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Pulley / Table



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