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Assuming a frictionless, massless pulley, ...

... determine the a of the block after the large block is released

Let's make clockwise positive

Fnet = ma

[Mg - mg] = (M + m)a

 

g(M - m)	=	a
(m + M)

Only applies when surface frictionless

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According to Newton's 2nd LAw the acceleration of the 2 masses
comes from weight difference and .....

Force of tension of the rope
on mass m, M?

Rule - One Rope, 
One Tension

Let's Make Clockwise Positive

ΣFy = Ma

Mg - Tf = Ma

Tf  = Mg - Ma

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