Recoil Problem — when interacting objects start from rest

Momentum Do Now warm-up prompt
Do Now
Try This At Home

Review – Explain this using one of Newton's Laws

A lead brick has a lot of mass and therefore a lot of inertia.

The greater the mass, the greater the tendency for an object to remain at rest, the smaller the acceleration that is produced by a given force.

Conservation of Momentum

Newton Collider

B) Recoil Problem

When interacting objects start from rest

Question

"What is the total momentum before cannon is fired?"

"Total momentum after clown is fired?"

[ Flash ]

↓

"Total momentum before = 0. (at rest)"

"Total momentum after = 0. (momenta are equal but opposite.)"

Gangster shooting a machine gun
Question

"In real life, it would be foolish to shoot a rifle like this. Why?"

Gangster shooting a machine gun
↓

"The recoil on that rifle would throw the shooter's shoulder out!"

Ex 1) Rifle Recoil

A 4.0 kg rifle fires a 5.0 × 10-3 kg bullet at a velocity of 500. m/s. What is the velocity acquired by the rifle? (no shooter)

Rifle

After rifle is fired

Rifle Bullet
mR = 4.0 kg mB = 5.0 × 10-3 kg
VR = ? VB = 500. m/s

Total Momentum Before = Total Momenta After Interaction

0 = m1V1 + m2V2

Subtract m2V2 from both sides:

m1v1 = −m2V2

In problem solving, remove the negative sign and use:

m1v1 = m2v2

(Not in Reference Table)

Important: Regents almost always has a question that asks you to use this equation.

(4.0 kg)V = (5.0 × 10-3 kg)(500. m/s)

(4.0 kg)V = 2.5 kg·m/s

↓

V = .63 m/s

Equal vs. Unequal Mass Explosions

Machine
Momenta before/after = 0 before

Equal Mass

cars_explosion.mpg

W.F.U.

Total momentum after = 0 ??

carsExplosionUneq.mpg

W.F.U.

↓

Yes, the slower cart has a greater mass.

Ex 2) Magnet Momentum

Two disk magnets are arranged at rest on a frictionless horizontal surface.

Two disk magnets at rest on a frictionless surface

When the string holding them together is cut, they move apart under a magnetic force of repulsion.

a) What is the total momentum of the magnets before the string is cut?

↓

Total momentum before = 0

(Both objects begin at rest)

b) What is the total momentum of the magnets after the string is cut?

↓

Total momentum after = 0

(Total mom. before = Total mom. after)

c) What is the velocity of the 1.0 kg mass when the velocity of the 2.0 kg magnet is 30. m/s?

[ Flash ]

Magnet 1 Magnet 2
m1 = 2.0 kg m2 = 1.0 kg
V1 = 30. m/s V2 = ?

m1v1 = m2v2

2.0 kg(30. m/s) = 1.0 kg(V)

↓

V = 60. m/s

One More

What is the velocity of the cannon below?

Cannon momentum diagram

m1v1 = m2v2

500 kg(V1) = 100 kg(15 m/s)

↓

V1 = 3 m/s

Related

Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. A cannon at rest fires a ball. What is the total momentum of the cannon and ball just after firing?

2. A 4.0 kg rifle fires a 5.0 × 10⁻³ kg bullet at 500. m/s. What is the rifle's recoil speed?

3. Two magnets at rest push apart. The 2.0 kg magnet moves at 30. m/s. How fast does the 1.0 kg magnet move?

4. A 500 kg cannon fires a 100 kg ball at 15 m/s. What is the cannon's recoil speed?

5. Two carts at rest are pushed apart by a spring. One cart moves away more slowly. What does that tell you?

NYSSLS Regents Practice · Momentum · Recoil

Rifle Recoil

At a target range, a 4.0-kg rifle fires a 0.010-kg bullet. The bullet leaves the barrel at 800. m/s. Before firing, the rifle and bullet are at rest.

What is the recoil speed of the rifle if it is free to move?

▶ Want a challenge? Open 6 more Regents-style questions  (harder · mixed formats)

Challenge score: 0 / 6

Draw the vector · Determine the magnitude

C1. The bullet is fired to the right. The bullet takes 0.0020 s to accelerate along the barrel. Choose the direction of the average force the bullet exerts on the rifle, and determine its magnitude.

rifle
●
F = N
Multiple choice

C2. Why do shooters press the rifle firmly against their shoulder?

Substitute values

C3. A 76-kg shooter holds the 4.0-kg rifle firmly against his shoulder so that rifle and shooter recoil together. Substitute numerical values into a mathematical representation that can be used to determine the recoil speed of the rifle–shooter combination. Then calculate the speed.

v = ( kg)( m/s)( kg) = m/s
Support or Refute · Justify

C4. A student makes the following claim.

Claim: If the same 4.0-kg rifle fired a heavier 0.020-kg bullet at 400. m/s, the rifle would recoil more slowly than it does with the 0.010-kg bullet at 800. m/s.

Place a check mark in either the Support or Refute box. Justify your response using a mathematical relationship.

Multiple choice

C5. What are the kinetic energies of the bullet and the free rifle just after firing?

Constructed response

C6. A rifle designer considers making the rifle heavier to reduce recoil. Identify one benefit and one drawback of this design change, using momentum to explain the benefit.