AP Physics
Conservation of Momentum
Elastic Collision?
No energy lost in collision
(1/2)m_{1}v_{1}^{2 }+ (1/2)m_{2}v_{2}^{2 }= (1/2)m_{1}v_{1f}^{2 }+ (1/2)m_{2}v_{2f}^{2}
^{Combine equations above with} m_{1}v_{1} + m_{2}v_{2} = m_{1}v_{1}′ + m_{2}v_{2}′ ^{you get .....} V_{1}  V_{2} = V_{2}'  V_{1}'
Giancoli  page 189) 23
V_{1 } V_{2 }= V_{2}  V_{1} V_{2}  V_{1 } = 3 m/s V_{2} = 3 m/s + V_{1}
1.35 kgm/s = .45V_{1} + .90kg(3+V_{1})
1.35 = 1.35V_{1}^{'} + 2.7 V_{1}^{'}=^{ }1 m/s or 1 m/s West
V_{2} = 3 m/s + V_{1} then ... V_{2} = 2 m/s East
_{Collisions in 2 Dimensions} _{Momentum is conserved in x and y directions} a^{2} + b^{2} = c^{2}
Textbook  p. 190) 41 Total Momentum Before a^{2} + b^{2} = c^{2} Eagle 1: mv = 4.3 kg(7.8m/s) = 34 kgm/s Eagle 2: mv = 5.6kg(10.2 m/s) = 57kgm/s Total Mom before: a^{2} + b^{2} = c^{2} 34^{2} + 57^{2} = c^{2} Total mom before = 66 kgm/s 66 kgm/s = (5.6kg + 4.3kg)v
V = 6.7 m/s
problem 42)
Gravity, Friction Momentum
Enrichment
Georgia Public Broadcasting Momentum Video
ŠTony Mangiacapre.,  All Rights Reserved
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