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Coulombs Law Notes
F) Coulomb's Law for two fixed point charges
r = distance between charges
F - mutual force of attraction
or repulsion q - charge of each object k - electrostatic constant - 8.99 x 109
Nm2/C2
AP Physics
AP Physics Giancoli p. 465) 12 12.
Ex) What is the electrical force between 2 very small objects located .50 m apart when the charge on one object is 4.0 x 10-8 C and the charge on the second object is 6.0 x 10-5 C
Ex) What is the electrical force between 2 very small objects located .50 m apart when the charge on one object is 4.0 x 10-8 C and the charge on the second object is 6.0 x 10-5 C
r = .50 meters q1 = 4.0 x 10-8 C q2 = 6.0 x 10-5 C k = 8.99 x 109 Nm2/C2
F = 8.6 x 10–2 Newtons
Relationships
F,r
Inverse Square
Relationship between F and r?
How would doubling the distance between the charges change the force between them?
F would be 1/4 as great
F,q?
Direct
Two charges attract each other with a force of F. If one charged was doubled and the other charge was tripled, how would that change the attractive force between these charges?
Force increases 6 times
Charged
Water Drop
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