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		 Physics Fun with Gum 
 (Seem to need a large stick of gun to make this work.) 
 
 I.) Electric Potential - work needed or energy acquired when a positive charge is moved from infinity to a certain point in an electric field. 
 
 
 II) Potential Difference (Voltage) potential energy difference between 2 points in an electric field per unit of charge 
 
 
 
 A) Potential Difference, Energy & Work As a charge moves through an electric field it gains PE or KE 
 
 
 If "Opposites" move Closer ![]() 
 Gain KE or PE? 
 
 
 They Gain KE 
 
 
 
		 
 
 
 'Opposites' Separate Gain KE or PE? 
 
 
 
 They Gain PE 
 
 
 
		 
 
 
 If "Likes" Separate 
				 Gain KE or PE? 
 
 
 They Gain KE 
 
 
 
		 
 
 
 If 'Likes' move... 
 closer 
 Gain KE or PE? 
 
 
 They Gain PE 
 
		 
 
 1) Equation #1 
 
 
 
 W = work done against field or energy acquired working with field (Joules or eV) 
 eV = electronVolts (small energy unit) 
  q 
		- amount of charge moving through field (Coulombs) V 
		- Potential Difference (volts) 
 
 
 
 
 Ex) It takes 6 Joules of work to move 2 coulombs of charge between 2 points in an electric field. What is the potential energy difference (voltage) between these 2 points? 
 
 
 
 
 
 
 
 V = 3 Volts or J/C 
 
 
 2) Potential difference (V) #2 
 
 
 
 W = work done against field 
		or energy acquired working with field 
		 (Electronvolts = Ev) 
 
  Electronvolt 
 
 
 q - amount of charge moving through field (# elementary charges) 
 V - Potential Difference (volts) 
 
 
 
 Ex) It takes 10 eV to move 2 elementary charges from one point to another in an electric field. Find the potential difference between these points. 
 
 
 
 
 
 
 V = 5 Volts 
 
 
 
 
 
 Ex) +2 elementary charges acquire 16 joules of energy when they move between 2 points in an electric field. What is the potential difference (voltage) between these two points in the field? Units don't match!!! 
 elementary charges, eV Joules/Coulombs 
 +2 elementary charges= 3.2 x 10-19 C 
 
 
 
 
 
 
 
 Calculator Review 
 
 
 V = 5.0 x 1019 Volts 
 or J/C 
 
 
 
 
 
 
 
 
 
 
 
		 W = 4.8 x 10-17 Joule V = ? q = ? 
 Hint: The charge in this problem is an electron 
 
  q = 1.6 x 10-19 
		C 
 
 
 
 
 V = 4.8 x 10-17 J / (1.6 x 10-19)C 
 
 a) 3.0 x 102 V 
 
 
 
		 
 
 
		 
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