Simple Harmonic Motion Problems with Solutions

Simple Harmonic Motion

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KE₁ + PE₁ = KE₂ + PE₂

Where is the a the greatest? smallest?

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a is greatest at ends (F is greatest)

a = 0 in middle since F = 0

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Period

- time for one full cycle

- determined by ....

mass and k

m = mass in kg

k = spring constant = F/x (N/m)

T = 1/f

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PE at C equals .....

KE at B

Ex) Mass M is attached to a spring with a spring constant k

If the maximum displacement of a mass M from its equilibrium position is A, find the velocity of the mass at B is

PE_max = KE

1/2kA² = 1/2mv²

Velocity Amplitude Direct

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PHET Animation