Do Now warm-up prompt

Angle ≠ 90° — when concurrent forces don't meet at a right angle, the resultant can't be found with the Pythagorean theorem. It must be found graphically.

Ranking Task

Rank the resultants from smallest to largest

Ranking task diagram of several force-vector pairs

Jan 2006

Flash

F. Resultants When the Angle Between Forces ≠ 90°

Given

5 N North & 3 N 30° S of E act concurrently (on a single point).
Find the resultant & equilibrant.

Angle not 90 degrees, can't use Pythagorean theorem

Graphical Method

1. Draw vectors to scale

Two force vectors drawn to scale

2. Make parallelogram

Parallelogram constructed from the two vectors

3. Draw diagonal (resultant)

Diagonal of the parallelogram drawn as the resultant

4. Find magnitude & direction of vector

Graphical Method

1. Measure length, convert to Newtons using scale 1 cm = 1 N

2. Measure angle vector makes with horizontal

↓

Resultant

R = 4.5 N 53° N of E

Equilibrant

E = 4.5 N 53° S of W

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Show Me The Physics

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St. Mary's U. Astronomy and Physics Dept.

When a fluid moves in a single direction, it exerts very little pressure perpendicular to the direction of its flow. The external air pressure keeps the ball in place.

Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. Why can't the Pythagorean theorem find the resultant of two forces at 30° to each other?

2. In the parallelogram method, after drawing both vectors to scale from one point, the resultant is

3. Using a scale of 1 cm = 1 N, a resultant drawn with the graphical method measures 4.5 cm. What is its magnitude?

4. A resultant is 4.5 N, 53° N of E. What is the equilibrant?

5. Forces of 5 N and 3 N act on a point at an angle other than 0°, 90° or 180°. Which resultant is possible?

NYSSLS Regents Practice · Forces · Models & Measurement

Two Ropes on a Sled

Two students pull a sled across flat snow using two ropes. Each student pulls with a horizontal force of 50. N. The angle between the two ropes is 60.°, and the sled moves along the line that splits this angle in half.

Which value is closest to the magnitude of the resultant of the two forces?

▶ Want a challenge? Open 6 more Regents-style questions  (harder · mixed formats)

Challenge score: 0 / 6

Determine the value

C1. Each 50.-N rope force can be split into a component along the sled’s path and a component perpendicular (sideways) to it. Determine the magnitude of the sideways component of one rope’s force.

Fside = N
Multiple choice

C2. If the angle between the ropes is increased to 120°, what is the resultant?

Support or Refute · Justify

C3. A student makes the following claim.

Claim: When the students pull with the ropes 60.° apart, the sideways parts of their two forces cancel, so only the parts along the sled’s path contribute to the resultant.

Place a check mark in either the Support or Refute box. Justify your response using a mathematical relationship.

Substitute values

C4. The students move closer together so the angle between the ropes is 40.°. Each still pulls with 50. N. Substitute numerical values into a mathematical representation that can be used to determine the magnitude of the resultant. Then calculate the resultant.

R = 2F cos(θ/2) = 2( N)(cos °) = N
Multiple choice

C5. Which list ranks the resultant from greatest to least for angles of 0°, 60.°, 90.°, and 120°?

Constructed response

C6. The students want the largest possible pull on the sled, but if their ropes are too close together they bump into each other. Identify one benefit and one drawback of increasing the angle between the ropes.