Video Instruction showmethephysics.com
B. Free fall - falling where the only force is gravity (no friction)
1. Free fall Word Problems
'…an object is dropped'
Vi = 0
a = g = +9.8m/s2 …
an object is ascending:
a
= g = -9.8 m/s2
V vs t plot, Object Ascending?
Ex) Object thrown up Vi
= 110 m/s,
a. Simple Freefall Problems
Ex) A coin is dropped in a vacuum tube, find its displacement after .30 seconds.
d = Vit + 1/2at2
d = 0m/s(.30 sec)+1/2(9.8 m/s2)(.30 s)2
d = 0 + 4.9(.09)
d = .44 m
Ex) A coin is dropped in a vacuum tube, find the coin's velocity after .30 seconds
Ex) A coin is dropped in a vacuum tube, find the coin's velocity after .30 seconds
Vi = 0 m/s a = +9.8 m/s2 (dropped) Vf = ? t = .30 sec
Vf = Vi + at OR a = (Vf - Vi)/t
Vf = 0 + 9.8 m/s2(.3 sec)
Vf = 2.9 m/s
Ex) A rocket is fired vertically upward with an initial velocity of 29 m/s.
Find the rocket's maximum altitude.
Ex) A rocket is fired vertically upward with an initial velocity of 29 m/s . Find the rocket's maximum altitude.
Altitude?? Vi = +29 m/s Vf = 0 m/s d = ?
(0 m/s)2=(+29 m/s)2+2(-9.8m/s2)d
0 = 841 + -19.6d
-841 = -19.6d
43 m
Uniform or Non-uniform Acceleration?
Ex) An object dropped on planet X falls 64 m in 4 seconds. Find the acceleration due to gravity on planet X.
Vi=
0 m/s
d = Vit + 1/2 at2
64 m = 0 m/s(4 sec) + 1/2a(4
sec)2
64 m = 0 + 8a
a = 8 m/s2
AP Question A ball is thrown upward from a position (y0)above the ground with a velocity of 16 m/s.
Find y0 if it took 3.0 seconds for the ball to hit the ground.
A ball is thrown upward from a position (y0) above the ground with a velocity of 8 m/s.
Find y0 if it took 3.0 seconds for the ball to hit the ground. ay = -10. m/s2 (g) yi = ? Vi = 8 m/s yf = 0 (hit the ground) t = 3.0 sec
∆d = Vit + 1/2at2 yf - yi = Vit + 1/2at2 y = yi + Vit + 1/2at2 0 = yi + 8 m/s(3.0 sec) + 1/2(-10.m/s2)(3.0 sec)2 0 = yi + 24 m + -45 m
-yi = 24 m + -45 m -yi = -21 m yi = 21 m
What velocity does the ball to hit the ground? Make down positive Make this a problem of a ball falling from a height of 21 m and a velocity of 8 m/s down ay = +10. m/s2 (g) ∆d = +21 m Vi = +8.0 m/s (vel. become +8 m/s when ball returns to original position) Vf = ? Vf2 = Vi2 + 2ad Vf2 = 64 + 2(10 m/s2)21m
Vf = 22 m/s down
OR
Vf = 8.0m/s + -10m/s2(3 sec)
Vf = -22 m/s
Paul Hewitt Question When you drop a ball it accelerates downward at 9.8 m/s2. If you instead throw it downward, then its acceleration immediately after leaving your hand, assuming no air resistance, is A. 9.8 m/s2. B. more than 9.8 m/s2. C. less than 9.8 m/s2. D. Cannot say, unless the speed of throw is given.
Ex) A basketball player jumped straight up to grab a rebound. If she was in the air for 0.80 second, how high did she jump?
Treat this as a problem where the player comes down from the peak of her rebound.
ay = 10. m/s2 (g) d = ? Vi = 0 m/s t = .40 sec
∆d = Vit + 1/2at2
∆d = 1/2(10 m/s2)(.4 sec)2
∆d = .80 m
Ex) A stone is thrown vertically upward with a speed of 12.0 m/s from the edge of a cliff 70.0 m high. a) how long does it take to reach the bottom of the cliff?
t = ? (how long) ay = 9.80 m/s2 (down positive) Viy = -12.0 m/s2 ∆dy = +70.0 m (down positive)
∆dy = Viyt + 1/2ayt2
70.0 m = -12.0 m/s2t + 4.9 m/s2t2
0 = -12.0 m/s2t + 4.9 m/s2t2 - 70 m
Quadratic, positive root = 5.20 sec
©Tony Mangiacapre., - All Rights Reserved [Home]
|
|||||||||||||||