AP Physics 1 Kinematics
Concept Challenges

Ten sense-making tasks on motion in one and two dimensions. Explain your reasoning for every answer. The explanation counts as much as the answer.

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Ranking Task

1. Time in the Air

Six balls are launched from level ground with the speeds and angles shown. Ignore air resistance. Each ball lands back on the same level ground.

A 20 m/s 30° m = 2 kg B 10 m/s straight up m = 5 kg C 20 m/s 60° m = 1 kg D 40 m/s 30° m = 3 kg E 30 m/s 30° m = 4 kg F 20 m/s straight up m = 0.5 kg

Rank the balls by their time in the air, from longest to shortest. If any are equal, show the tie. If the ranking cannot be determined, say so.

Longest 1 ____ 2 ____ 3 ____ 4 ____ 5 ____ 6 ____ Shortest

Explain your reasoning.

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Conflicting Contentions

2. Dropped vs. Thrown

Ball A is dropped from the top of a 20 m cliff. At the same instant, an identical Ball B is thrown horizontally at 15 m/s from an identical 20 m cliff. Ignore air resistance. Three students argue about which ball hits the ground first.

Ball A: dropped 20 m released from rest Ball B: thrown horizontally 20 m 15 m/s

Ava: "Ball A lands first. Ball B has to travel a longer path, so it takes more time."

Ben: "Ball B lands first. It's moving faster the whole time, so it gets there sooner."

Cam: "They land at the same time. The horizontal motion doesn't change how fast each ball falls."

Which student(s), if any, do you agree with? Explain what is right or wrong about each statement. Then find the time each ball takes to land.

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What, If Anything, Is Wrong?

3. Velocity Along the Path

A soccer ball is kicked from level ground and follows the dashed path. Ignore air resistance. A student draws the ball's velocity vector at five points. At the top (point R), the student writes "v = 0" because "the ball stops going up."

v = 0 P Q R (top) S T

What, if anything, is wrong with the student's diagram? If something is wrong, explain the error and describe the correct vector(s). If nothing is wrong, explain why it is correct.

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Linked Multiple Choice

4. Sign of the Acceleration

A cart moves along a straight horizontal track. To the right is the positive direction. For each situation, choose the sign of the cart's acceleration:

cart + direction

A. positive    B. negative    C. zero    D. cannot be determined

SituationChoice
(a) Moving right and speeding up
(b) Moving right and slowing down
(c) Moving left and speeding up
(d) Moving left and slowing down
(e) Moving left at a constant 3 m/s
(f) Rolled up a ramp that rises to the right, momentarily at rest at its highest point
(g) At rest at one instant (no other information)

Explain the rule you used. Does "negative acceleration" always mean "slowing down"?

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Comparison Task

5. Up or Down?

From the edge of a 25 m tall roof, Ball 1 is thrown straight up at 20 m/s and an identical Ball 2 is thrown straight down at 20 m/s. Ignore air resistance.

25 m 20 m/s Ball 1 20 m/s Ball 2

For each quantity, state whether it is greater for Ball 1, greater for Ball 2, the same for both, or cannot be determined.

QuantityAnswer
(a) Acceleration halfway through each ball's flight
(b) Time from release until hitting the ground
(c) Displacement from release until hitting the ground
(d) Speed just before hitting the ground

Explain each answer. Then check (b) and (d) with numbers, using $g = 10\ \text{m/s}^2$.

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Predict & Explain

6. Ball Launched From a Moving Cart

A cart rolls to the right at a constant 3.0 m/s. A spring launcher on the cart fires a ball straight up (relative to the cart) at 5.0 m/s. Ignore air resistance.

5.0 m/s (relative to cart) 3.0 m/s cart
  1. Predict before calculating: does the ball land in front of the launcher, behind it, or back in it? Explain.
  2. Describe the ball's path as seen by a student standing on the ground.
  3. Check your prediction: how long is the ball in the air, and how far do the ball and the cart each move horizontally?
  4. Now the cart speeds up at 2.0 m/s² during the ball's flight (starting at 3.0 m/s when the ball is fired). Where does the ball land now?
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Working Backwards (Jeopardy)

7. Write the Problem

The two equations below describe the motion of one object in some physical situation:

$$-45\ \text{m} = (0\ \text{m/s})\,t - \tfrac{1}{2}(10\ \text{m/s}^2)\,t^2$$

$$\Delta x = (12\ \text{m/s})\,t$$

  1. Describe a physical situation these equations could represent. Say what each number stands for, and what the "0" tells you about how the motion starts.
  2. Sketch the path of the object.
  3. Solve for $t$ and $\Delta x$.
  4. If the $12\ \text{m/s}$ were changed to $24\ \text{m/s}$, how would $t$ and $\Delta x$ change? Explain without re-solving.
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Changing Representations

8. From x–t Graph to v–t Graph

The graph shows the position of a toy car moving along a straight hallway.

012345678 time (s) −4−202468 x (m)
  1. Sketch the velocity vs. time graph on the blank axes below. Label values with units.
  2. When is the car farthest from its starting point? How far is it, and in which direction?
  3. Find the car's total distance traveled and its displacement from 0 s to 8 s.
  4. A student says, "From 4 s to 8 s the car is rolling down a hill." Respond to the student.
12345678 t (s) −6−4−20246 v (m/s)
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Troubleshooting

9. Find the Mistake

A soccer ball is kicked from level ground at 25 m/s, 37° above the horizontal. Find how far away it lands. Use $g = 10\ \text{m/s}^2$, $\sin37^\circ = 0.60$, $\cos37^\circ = 0.80$. Ignore air resistance.

37° 25 m/s level ground

Student solution:

$v_x = (25\ \text{m/s})\cos37^\circ = 20\ \text{m/s}$

Time to reach the top: $0 = 25\ \text{m/s} - (10\ \text{m/s}^2)t \Rightarrow t = 2.5\ \text{s}$

Total time in air: $2(2.5\ \text{s}) = 5.0\ \text{s}$

Range: $\Delta x = (20\ \text{m/s})(5.0\ \text{s}) = 100\ \text{m}$

Identify the error in the solution. Explain the physics of why it's an error, then find the correct range.

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Meaningful / Meaningless Calculation

10. Average Velocity of a Round Trip

A driver goes from home to a store 30 km east at a steady 60 km/h. On the way back (30 km west), traffic is heavy and she drives at a steady 30 km/h.

HomeStore Trip out: 30 km east at 60 km/h Trip back: 30 km west at 30 km/h 30 km

Riley writes: "Her average velocity for the whole trip is $\dfrac{60\ \text{km/h} + 30\ \text{km/h}}{2} = 45\ \text{km/h}$."

  1. Is Riley's calculation physically meaningful for this trip? Explain.
  2. What is the driver's actual average velocity for the round trip?
  3. What is her average speed? Is it greater than, less than, or equal to 45 km/h? Explain why without a formula.
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